Question

1.
How many kJ are required to completely vaporize a 250 gram sample of water at 100°C?
general formula

Answer 1

Answer:

565 kJ

Explanation:

$H_v$ = Heat of vaporization of water at 100°C = 2260 J/g

m = Mass of water = 250 g

Heat required is given by

$Q=mH_v$

$\Rightarrow Q=250\times 2260$

$\Rightarrow Q=565000\ \text{J}$

$\Rightarrow Q=565\times 10^3\ \text{J}$

$\Rightarrow Q=565\ \text{kJ}$

The heat required to vaporize the water is 565 kJ.