Question

In sailing, it is not possible to head straight into the wind. In order to get upwind, a sailboat simply sails at an angle to the wind and then turns to sail back toward where it wants to go. Assume that a boat needs to get directly upwind 6000 m. If it sails off at a 45 degree angle to the wind and then turns back 90 degrees towards the original goal, how far would it have to sail to get directly upwind 6000 meters? Round to the nearest tenth.

Distance to get directly upwind 6000 meters: ____________________ meters
6000

4242.6

8485.3

10392.3

Answer 1

Answer:

C. 8485.3 meters

Step-by-step explanation:

Think of the sailboat’s path as a 45-45-90 right triangle.

The hypotenuse is the 6000 meter distance.

In this way the leg will be the hypotenuse divided by √2.

So 6000/√2 or 4242.64 meters.

Remember that the sailboat has to turn and head back toward its goal and travel another 4242.64 meters.

Thus, your answer is 4242.64 x 2 = 8485.28 meters or 8485.3 meters.

Answer 2

In this exercise we have to use the knowledge of triangles to calculate the distance that one of the sides has:

Letter C

Some information given in the statement about the triangle:

• Sailboat’s path as a 45-45-90 right triangle.

• The hypotenuse is the 6000 meter distance.

So performing the calculation we have:

$6000\sqrt{2}=4242.64 \\4242.64 * 2 = 8485.28$

See more about triangles at brainly.com/question/25813512