Question

A company makes two mixtures of nuts: mixture A and mixture B. Mixture A contains 30% peanuts, 30% almonds and 40% cashews and sells for $5 per pound. Mixture B contains 30% peanuts, 60% almonds and 10% cashews and sells for $3 a pound. The company has 540 pounds of peanuts, 900 pounds of almonds, 480 pounds of cashews. What is the companies maximum profit from selling both mixture A and mixture B?

Answer 1

Answer:

1,000 pounds of mixture A

800 pounds of mixture B

maximum profit = $7,400

Step-by-step explanation:

mixture A = 0.3P + 0.3A + 0.4C

mixture B = 0.3P + 0.6A + 0.1C

maximize = 5A + 3B

0.3A + 0.3B ≤ 540

0.3A + 0.6B ≤ 900

0.4A + 0.1B ≤ 480

A ≥ 0

B ≥ 0

using solver, the optimal solution is: 1,000A + 800B = $7,400 maximum profit

 

Answer 2

The companies maximum profit from selling both mixture A and mixture B is 1,000 pounds of mixture A, 800 pounds of mixture B, and maximum profit = $7,400

Calculation of the maximum profit:

Since

mixture A = 0.3P + 0.3A + 0.4C

mixture B = 0.3P + 0.6A + 0.1C

maximize = 5A + 3B

So,

0.3A + 0.3B ≤ 540

0.3A + 0.6B ≤ 900

0.4A + 0.1B ≤ 480

A ≥ 0

B ≥ 0

Here we used solver, so the optimal solution is

1,000A + 800B = $7,400 maximum profit

Learn more about the profit here: https://brainly.com/question/24599492