Question

Beverly and Carl are in a race. Their graphs show the data.

A graph with horizontal axis time (seconds) and vertical axis velocity (meters per second). An orange line labeled Beverly starts at 0 seconds 0 meters and goes straight to 10 seconds 15 meters and then to 50 seconds 35 meters. A blue line labeled starts at 0 seconds 0 meters and goes straight to 10 seconds 10 meters and then to 50 seconds 30 meters.

Which best describes the race?

Even though for a majority of the race they accelerated at the same rate, Carl won because his initial acceleration was greater than Beverly’s.
Even though for a majority of the race they accelerated at the same rate, Beverly won because her initial acceleration was greater than Carl’s.
Beverly accelerated at a greater rate for the entire race.
Carl accelerated at a greater rate for the entire race.

Answer 1

Answer:

the answer is:

Even though for a majority of the race they accelerated at the same rate, Beverly won because her initial acceleration was greater than Carl’s. Please choose brainliest i have never gotten it but its correct. the answer in edge is letter C ok hope this helps.

Explanation:

Answer 2

Even though for a majority of the race they accelerated at the same rate, Beverly won because her initial acceleration was greater than Carl’s.

The given parameters are listed as follows:

For Beverly: initial time of motion, t₁ = 10 s

                     initial velocity, u = 15 m/s

                     final time of motion, t₂ = 50 s

                     final velocity, v = 35 m/s

For Carl: initial time of motion, t₁ = 10 s

               initial velocity, u = 10 m/s

               final time of motion, t₂ = 50 s

               final velocity, v = 30 m/s

The initial acceleration of Beverly is calculated as:

$initial \ acceleration \ of \ Beverly = \frac{initial \ velocity}{initial \ time} = \frac{15 \ m/s}{10 \ s} = 1.5 \ m/s^2$

The average acceleration of Beverly is calculated as:

$a = \frac{\Delta v}{\Delta t} = \frac{v-u}{t_2 - t_1} = \frac{35 - 15}{50-10} = \frac{20}{40} =0.5 \ m/s^2$

The initial acceleration of Carl is calculated as:

$initial \ acceleration \ of \ Carl = \frac{initial \ velocity}{initial \ time} = \frac{10 \ m/s}{10 \ s} = 1.0 \ m/s^2$

The average acceleration of Carl is calculated as:

$a = \frac{\Delta v}{\Delta t} = \frac{v-u}{t_2 - t_1} = \frac{30 - 10}{50-10} = \frac{20}{40} =0.5 \ m/s^2$

In summary, Beverly and Carly had the same average acceleration for the majority of the race but the initial acceleration of Beverly was higher than that of Carl, hence Beverly won the race.

Learn more here: https://brainly.com/question/10825896