Answer:
x = 31°
Step-by-step explanation:
[tex]\triangle ABC \cong \triangle DCE... (given) \\\\
\therefore m\angle B = m\angle E..(cact)\\\\
\because m\angle B = 61\degree \\\\
\therefore m\angle E = 61\degree \\\\
In \: \triangle DCE\\\\
m\angle D+ m\angle C + m\angle E = 180\degree \\
(by \: interior \: angle \: sum \: property \: of \: a triangle) \\\\
2x\degree + 57\degree + 61\degree= 180\degree \\\\
2x\degree + 118\degree = 180\degree \\\\
2x\degree = 180\degree - 118\degree \\\\
2x\degree = 62\degree \\\\
x = \frac{62\degree}{2} \\\\
x = 31\degree
[/tex]
