Answer:
if the number of moles increase the volume will also increase. If a lower volume was recorded alower calculated molar mass would be observed because, there would be less of a volume overyour number of moles because the number of moles of Hydrogen gas is found theoretically withhow much Mg was used.8. A student noticed that the magnesium ribbon appeared to be oxidized—the metal surface wasblack and dull rather than silver and shiny. What effect would this error have on the measuredvolume of hydrogen gas? Would the calculated molar volume of hydrogen be too high or toolow as a result of this error? Explain.If the Mg ribbon was oxidized, the volume of Hydrogen gas recorded would be less thanthe idealized result because less Mg would react to make Hydrogen gas. This would result in themolar volume decreasing because there would be less volume per mole hydrogen. The decreasedmolar volume would contribute to a larger density because the mass would be divided by asmaller volume.ConclusionThe purpose of this lab was to determine the molar volume of H2(g)at STP. We were ableto carry out this task by reacting a known amount of Mg with HCl in a eudiometer tube filledwith water so that volume of the gas created would be measurable. The main purpose of the lab
Explanation:
because if you increase the number then you get this
If a student uses a magnesium ribbon that has been oxidized, the molar volume of hydrogen be too high.
Magnesium, like all other metals become tarnished when exposed to oxygen. This tarnishing is due to oxidation of the magnesium. When magnesium is oxidized, magnesium oxide is formed.
When this occurs, the amount of Mg available for the reaction; 2Mg(s) + O2(g) ----> 2MgO decreases. Since the molar volume of hydrogen is calculated from the mass of magnesium metal used, the molar volume of hydrogen is found to be too high.
Learn more: https://brainly.com/question/9743981
