A certain mass of nitrogen gas occupies a volume of 7.56 L at a pressure of 5.08 atm. At what pressure will the volume of this sample be 9.94 L?

Respuesta :

Answer:

P₂ = 3.86 atm .

Explanation:

We assume that during this change , the temperature of the gas remains constant .

So the gas will obey Boyle's law .

P₁ V₁ = P₂V₂

5.08 x 7.56 = P₂ x 9.94

P₂ = 3.86 atm .

Nitrogen gas was considered ideal in nature. The pressure of the gas at which the volume is 9.94 L is 3.84 atm.

What is Boyle's law?

Boyle's law was applied to give the relationship between the pressure and the volume of a gas at a constant temperature.

The relationship can be given as:

[tex]P_1V_1=P_2V_2[/tex]

The initial pressure of the gas, [tex]P_1=5.08\;\rm atm[/tex]

The initial volume of the gas, [tex]V_1=7.56\;\rm L[/tex]

The final volume of the gas, [tex]V_2=9.94\;\rm L[/tex]

Substituting the values, final pressure ([tex]P_2[/tex])  is given as:

[tex]5.05\;\times\;7.56=P_2\;\times\;9.94\\\\P_2=\dfrac{5.05\;\times\;7.56}{9.94} \\\\P_2=3.84\;\rm atm[/tex]

The final pressure of the nitrogen gas with the increase in volume is 3.84 atm.

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