A block of ice in the form of a cube has one edge 10 feet long. It is melting uniformly so that its dimensions decrease at a rate of 1/10 fps (feet per second). At what rate is the volume of the block changing when the edge is 5 feet long?

Respuesta :

Answer:

-7.5 ft^3/sec

OR

Volume is decreasing at the rate of 7.5 ft^3/sec

Step-by-step explanation:

Side of cube = 10 feet

Rate of decreasing of side of cube = [tex]\frac{1}{10}\ feet/sec[/tex]

OR

Rate of change of side of cube = [tex]-\frac{1}{10}\ feet/sec[/tex]

To find:

Rate of change in volume when the edge is 5 feet long = ?

Solution:

Volume of a cone is given by:

[tex]V =Side^3[/tex]

If side is [tex]a[/tex] units, then Volume can be written as:

[tex]V =a^3[/tex]

Differentiating w.r.to time:

[tex]\dfrac{dV}{dt} = 3a^2\dfrac{da}{dt}\\\Rightarrow \dfrac{dV}{dt} = 3\times 5^2(-\frac{1}{10})\\\Rightarrow \dfrac{dV}{dt} = -7.5 ft^3/sec[/tex]

Negative sign indicates that the volume is decreasing at the rate of 7.5 ft^3/sec