Answer:
-7.5 ft^3/sec
OR
Volume is decreasing at the rate of 7.5 ft^3/sec
Step-by-step explanation:
Side of cube = 10 feet
Rate of decreasing of side of cube = [tex]\frac{1}{10}\ feet/sec[/tex]
OR
Rate of change of side of cube = [tex]-\frac{1}{10}\ feet/sec[/tex]
To find:
Rate of change in volume when the edge is 5 feet long = ?
Solution:
Volume of a cone is given by:
[tex]V =Side^3[/tex]
If side is [tex]a[/tex] units, then Volume can be written as:
[tex]V =a^3[/tex]
Differentiating w.r.to time:
[tex]\dfrac{dV}{dt} = 3a^2\dfrac{da}{dt}\\\Rightarrow \dfrac{dV}{dt} = 3\times 5^2(-\frac{1}{10})\\\Rightarrow \dfrac{dV}{dt} = -7.5 ft^3/sec[/tex]
Negative sign indicates that the volume is decreasing at the rate of 7.5 ft^3/sec