Question

neon sign transformer has a 460W AC output with an rms voltage of 15 kV when connected to a normal household outlet. There are 500 turns of wire in the primary coil. How many turns of wire does the secondary coil have

Answer 1

Answer:

The number of turns in the secondary coil is 62,500 turns.

Explanation:

Given;

power of the transformer, P = 460 W

output voltage, V₂ = 15 kV = 15,000 V

input voltage of normal household outlet, V₁ = 120 V

number of turns in the primary coil, N₁ = 500 turns

number of turns in the secondary coil, N₂ = ?

Apply the following the transformer equation;

$\frac{N_2}{N_1} = \frac{V_2}{V_1}\\\\N_2 = \frac{V_2}{V_1}*N_1\\\\N_2 = \frac{15000}{120}*500\\\\N_2 = 62500 \ turns$

Therefore, the number of turns in the secondary coil is 62,500 turns.