Respuesta :
Complete Question
A random sample of 300 circuits generated 13 defectives. a. Use the data to test
[tex]H_o : p = 0.05[/tex]
Versus
[tex]H_1 : p \ne 0.05[/tex]
Use α = 0.05. Find the P-value for the test
Answer:
The p-value is [tex]p-value = 0.5949[/tex]
Step-by-step explanation:
From the question we are told that
The sample size is n = 300
The number of defective circuits is k = 13
Generally the sample proportion of defective circuits is mathematically represented as
[tex]\^ p = \frac{k}{n}[/tex]
=> [tex]\^ p = \frac{13}{300}[/tex]
=> [tex]\^ p = 0.0433[/tex]
Generally the standard Error is mathematically represented as
[tex]SE = \sqrt{\frac{p(1- p)}{n} }[/tex]
=> [tex]SE = \sqrt{\frac{0.05(1- 0.05)}{300} }[/tex]
=> [tex]SE = 0.0126[/tex]
Generally the test statistics is mathematically represented as
[tex]z = \frac{\^ p - p }{SE}[/tex]
=> [tex]z = \frac{0.0433 - 0.05 }{0.0126}[/tex]
=> [tex]z = -0.5317[/tex]
From the z table the area under the normal curve to the left corresponding to -0.5317 is
[tex](P < -0.5317 ) = 0.29747[/tex]
Generally the p-value is mathematically represented as
[tex]p-value = 2 * P(Z < -0.5317 )[/tex]
=> [tex]p-value = 2 * 0.29747[/tex]
=> [tex]p-value = 0.5949[/tex]