Answer:
The first and third quartile of the wingspans are 116.9 cm and 133.1 cm respectively.
Step-by-step explanation:
The first and third quartile of a normal distribution are:
[tex]Q_{1}=\mu-0.675\sigma\\\\Q_{3}=\mu+0.675\sigma[/tex]
The information provided is as follows:
[tex]\mu=125\\\sigma=12[/tex]
Compute the first and third quartile of the wingspans as follows:
[tex]Q_{1}=\mu-0.675\sigma=125-(0.675\times 12)=116.9\\\\Q_{3}=\mu+0.675\sigma=125+(0.675\times 12)=133.1[/tex]
Thus, the first and third quartile of the wingspans are 116.9 cm and 133.1 cm respectively.