Question

Only 35 % of the intensity of a polarized light wave passes through a polarizing filter. What is the angle between the electric field and the axis of the filter

Answer 1

Answer:

The angle between the electric field and the axis of the filter is 54⁰

Explanation:

Apply the equation for intensity of light through a polarizer.

$I = I_oCos^2 \theta$

where;

I is the intensity of the transmitted light

I₀ is the intensity of the incident light

θ is the incident angle

If only 35 % of the intensity of a polarized light wave passes through a polarizing filter, then the ratio of the intensity of the transmitted light to that of the intensity of the incident light is given by;

$\frac{I}{I_o} = Cos^2 \theta\\\\\frac{35}{100} = Cos^2 \theta\\\\Cos^2 \theta = 0.35\\\\Cos\theta = \sqrt{0.35} \\\\Cos\theta = 0.5916\\\\\theta = Cos^{-1}(0.5916)\\\\\theta = 54 ^0$

Therefore, the angle between the electric field and the axis of the filter is 54⁰

Answer 2

The angle between the electric field and the axis of the filter for the polarized light wave which passes through a polarizing filter is 54°.

What is electric field?

The electric field is the field, which is surrounded by the electric charged. The electric field is the electric force per unit charge.

From the Malus's law, the intensity of the polarized beam can be calculated with the following formula.

$I=I_o\cos^2\theta$

Here, (I₀) is the intensity of the polarized beam incident on the observer θ is the angle of incident.

It is given that only 35 % of the intensity of a polarized light wave passes through a polarizing filter.

The angle between the electric field and the axis of the filter can be found out using the above formula as,

$35\%=(100\%)\cos^2\theta\\\theta=\cos^{-1}\sqrt{\left(\dfrac{35}{100}\right)}\\\theta=54^o$

Hence, the angle between the electric field and the axis of the filter for the polarized light wave which passes through a polarizing filter is 54°.

Learn more about electric field here;

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