Answer:
310N
Explanation:
These are the options for the question
A)68N
B. 68N
C. 180N
D. 250N
the normal force of the floor on the crate can be calculated using below formula
N=W+ Fsin(x)
= mg+ Fsin(x)
m= mass of the crate= 25kg
g= acceleration due to gravity= 9.8m/s^2
We were told a force of 200n directed 20°below the horizontal
Which means angle(x)= 20°
We were given horizontal floor with a force of 200N I.e F= 200N
If we substitute these values into the formula above we have
N=mg+ Fsin(x)
= (25kg×9.8) + 200sin(20)
=313.5N
Hence, the the magnitude of the normal force of the floor on the crate is approximately 310N
CHECK THE ATTACHMENT FOR THE DIAGRAM
