Respuesta :
Answer:
The correct answer will be "9×10⁻³ m".
Explanation:
The given values are:
Number of lines
N = 125
As we know
The distance between the adjacent fringes is:
⇒ [tex]\frac{\lambda x}{d}[/tex]
Where, λx = Screen distance
d = slit width
and,
⇒ [tex]dSin \theta=m \lambda[/tex]
Where, [tex]d = \frac{1}{N}[/tex]
Hence,
⇒ [tex]\Delta\gamma=\frac{\lambda x}{d}[/tex]
[tex]=\lambda x\times N[/tex]
On substituting the values, we get
⇒ [tex]\Delta\gamma=575\times 10^{-9}\times 1.25\times \frac{125}{10^{-2}}[/tex]
⇒ [tex]\Delta\gamma=9\times 10^{-3} \ m[/tex]
