Question

Determine f(-2/3) for the function f(x)=3x²+2x+1​

Answer 1

Answer:

1

Step-by-step explanation:

To evaluate, substitute x = - $\frac{2}{3}$ into f(x), that is

f(- $\frac{2}{3}$ )

= 3(- $\frac{2}{3}$ )² + 2(- $\frac{2}{3}$ ) + 1

= 3($\frac{4}{9}$ ) - $\frac{4}{3}$ + 1

= $\frac{4}{3}$ - $\frac{4}{3}$ + 1

= 0 + 1

= 1

Answer 2

Answer:

1

Step-by-step explanation:

f(x) = 3x² + 2x + 1

f(-2/3) = 3x² + 2x +1

f(-2/3) = 3(-2/3)² + 2(-2/3) + 1          

Substitute the value in for all the x's

f(-2/3) = 3(4/9) + 2(-2/3) + 1

f(-2/3) = 12/9 + (-4/3) + 1

f(-2/3) = 4/3 + (-4/3) + 1                

Subtracting 4/3 by (-4/3) gets you 0 so I didn't write it down.

f(-2/3) = 1

So, the answer I got is 1