Question

Find three consecutive odd integers such that the sum of the smallest number and
twice the middle number is 10 more than the largest number.

Answer 1

Answer: The three consecutive odd numbers are 5 , 7 , and 9 .

Step-by-step explanation:

Let the three consecutive odd integers be x, x+2 , x+4

Smallest number = x

Middle number = x+2

Largest number = x+4

As per given,

(Smallest number )+ 2 (Middle number ) = 10 + (Largest number)

$\Rightarrow\ x+2(x+2)=10+x+4\\\\\Rightarrow\ x+2x+4=14+x\\\\\Rightarrow\ 3x+4=14+x\\\\\Rightarrow\ 3x-x=14-4\\\\\Rightarrow\ 2x=10\\\\\Rightarrow\ x=5$

Hence, Smallest number = 5

Middle number = 5+2 = 7

Largest number = 5+4 =9

hence, the three consecutive odd numbers are 5 , 7 , and 9 .