Answer:
Lines A and B are perpendicular.
Step-by-step explanation:
Line A goes through points (-2,3) and (-1,1).
Finding the slope of line A
[tex]\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]\left(x_1,\:y_1\right)=\left(-2,\:3\right),\:\left(x_2,\:y_2\right)=\left(-1,\:1\right)[/tex]
[tex]m=\frac{1-3}{-1-\left(-2\right)}[/tex]
[tex]m=-2[/tex]
Line B goes through points (0,-3) and (2,-2).
Finding the slope of line B
[tex]\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]\left(x_1,\:y_1\right)=\left(0,\:-3\right),\:\left(x_2,\:y_2\right)=\left(2,\:-2\right)[/tex]
[tex]m=\frac{-2-\left(-3\right)}{2-0}[/tex]
[tex]m=\frac{1}{2}[/tex]
Please note that the slope of line A is a negative reciprocal of line B and vice versa.
As we know that the slopes of two perpendicular lines are negative reciprocals of each other.
Therefore, lines A and B are perpendicular.