Question

A quantity with an initial value of 920 decays exponentially at a rate of 85% every week. What is the value of the quantity after 21 days, to the nearest hundredth?

Answer 1

Answer:

≈3.11

Step-by-step explanation:

Answer 2

The value of the quantity after 21 days, to the nearest hundredth, given the expoenential decay is 3.11.

What is the value of the quantity after 21 days?

When a quantity decays , it means that the value of the quantity declines with the passage of time.

The formula that can be used to determine the value of the quantity after a number of weeks is :

FV = P (1 - r)^n

Where:

• FV = Future value
• P =initial value
• R =rate of decay
• N = number of weeks = 21/7 = 3 weeks

920 x (1 - 0.85)^3

920 x 0.15^3 = 3.11

To learn more about exponential function, please check: brainly.com/question/18760477