1. Write an equation using x and y to represent the hanger.
x +
y =
x +
y
2. If x is 6, what is y?
![1 Write an equation using x and y to represent the hanger x y x y 2 If x is 6 what is y class=](https://us-static.z-dn.net/files/dd3/679dc642a115236585ea9d303ec79055.png)
Answer:
1. [tex] x + 3y = 4x + y [/tex]
2. [tex] y = 9 [/tex]
Step-by-step explanation:
1. x = weight of 1 triangle
y = 1 weight of rectangle
On our left, we have 1 triangle (1x) and (+) 3 rectangles (3y).
This will give us the expression: x + 3y.
On our right, we have 4 triangles (4x) and (+) 1 rectangle (1y).
This will give us 4x + y
herefore, we would have the following:
The equation that represents the hanger would be:
✅[tex] x + 3y = 4x + y [/tex]
2. Substitute x = 6 in [tex] x + 3y = 4x + y [/tex], to find y.
[tex] 6 + 3y = 4(6) + y [/tex]
[tex] 6 + 3y = 24 + y [/tex]
Collect like terms
[tex] 3y - y = 24 - 6 [/tex]
[tex] 2y = 18 [/tex]
Divide both sides by 2
[tex] y = \frac{18}{2} [/tex]
[tex] y = 9 [/tex]
The equation that represent hanger is , 3x-2y = 0
When x = 6 then y will be equal to 9.
From given figure, it is observed that , on right side of hanger 4 triangle and 1 square is present.
And on left side of hanger 3 square and 1 triangle is present.
Since, x represent the weight of one triangle and y represent weight of one square.
Weight of left side of hanger = 3y + x
Weight of right side of hanger = 4x + y
Since, Both side weight are equal.
1. Thus, equation of hanger is,
[tex]3y+x=4x+y\\\\3x-2y=0[/tex]
2. When x = 6,
[tex]3(6)-2y=0\\\\18-2y=0\\\\y=18/2=9[/tex]
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