Answer:
17 g Ba(NO₂)₂
General Formulas and Concepts:
Chemistry
- Stoichiometry
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
Step 1: Define
4.5 × 10²² molecules Ba(NO₂)₂
Step 2: Define conversion
Molar Mass of Ba - 137.33 g/mol
Molar Mass of N - 14.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Ba(NO₂)₂ - 137.33 + 2(14.01) + 4(16.00) = 229.35 g/mol
Step 3: Dimensional Analysis
[tex]4.5 \cdot 10^{22} \ mc \ Ba(NO_2)_2(\frac{1 \ mol \ Ba(NO_2)_2}{6.022 \cdot 10^{23} \ mc \ Ba(NO_2)_2} )(\frac{229.35 \ g \ Ba(NO_2)_2}{1 \ mol \ Ba(NO_2)_2} )[/tex]
= 17.1384 g Ba(NO₂)₂
Step 4: Check
We are given 2 sig figs. Follow sig fig rules.
17.1384 g Ba(NO₂)₂ ≈ 17 g Ba(NO₂)₂
