Question

factoring. 2n^2+4n+2=0

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Answer 1

2n^2 + 4n + 2 = 0
Divide both sides by 2:
n^2 + 2n + 1 = 0
Find two numbers that multiply to form C (1) and add together to form 2: these numbers are 1 and 1:
(n +1)(n+1) = 0
(n+1)^2 = 0
Therefore n+1 = 0
n = -1