Respuesta :
Using the points (0,14) and (10,0), the gradient of the line is (14-0)/(0-5) which simplifies to -7/5.
From these points, we can also see that when the x value is zero, the y value is 14. Therefore the y-intercept is 14.
We can then put this into the equation of a straight line, y=mx+c:
y = (-7/5)x + 14
From these points, we can also see that when the x value is zero, the y value is 14. Therefore the y-intercept is 14.
We can then put this into the equation of a straight line, y=mx+c:
y = (-7/5)x + 14
Answer:
Option A.
Step-by-step explanation:
If a line passes through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex], then the equation of line is
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
It is given that the line of best fit passes through the points (0,14) and (10,0).
Using the above formula the equation of best fit line is
[tex]y-14=\frac{0-14}{10-0}(x-0)[/tex]
[tex]y-14=\frac{-14}{10}(x)[/tex]
[tex]y-14=-\frac{7}{5}(x)[/tex]
Add 14 on both sides.
[tex]y-14+14=-\frac{7}{5}(x)+14[/tex]
[tex]y=-\frac{7}{5}(x)+14[/tex]
The equation of best fit line is [tex]y=-\frac{7}{5}(x)+14[/tex].
Therefore, the correct option is A.