Respuesta :

Answer:

the slope is 11/3

so distance is 130 or 11.4 in decimal form

Answer:

Exact distance = [tex]\sqrt{130}[/tex]

Approximate distance = 11.40175

Explanation:

We'll use the distance formula

[tex]d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{(1-(-2))^2+(7-(-4))^2}\\\\d = \sqrt{(1+2)^2+(7+4)^2}\\\\d = \sqrt{(3)^2+(11)^2}\\\\d = \sqrt{9+121}\\\\d = \sqrt{130} \ \ \text{ ... exact distance}\\\\d \approx 11.40175 \ \ \text{ ... approximate distance}\\\\[/tex]

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