Question

Marisol keeps track of her weekly quiz grades as shown in the table.

a. Complete the table

b. In which class did Marisol have the higher score?

c. Suppose Marisol scored a 96% on an english test. There were 50 questions on the test. How many did Marisol answer correctly?


Test / Number/Score/Total
Correct
____________________
Math/ 68 / /85
Science/ / 90% / 70

Answer 1

Answer for a.: Math: 68 80% 85 Science: 63 90% 70 Answer for b.: Science. Answer for c.: (I don't know, sorry.)

Answer 2

You are given such table:

$\begin{array}{cccc} \text{Test} & \text{Number Correct} & \text{Score} & \text{Total}\\ \text{Math} & 68 & __ & 85 \\ \text{Science} & __ & 90\% & 70\end{array}$

You have to fill the gaps.

1. Consider the proportion for Math

85 - 100%

68 - x%.

Then

$\dfrac{85}{68}=\dfrac{100}{x},\\ \\x=\dfrac{68\cdot 100}{85}=\dfrac{6800}{85}=80$

The score of math test is 80%.

Consider next proportion for Science

70 - 100%

y - 90%.

Then

$\dfrac{70}{y}=\dfrac{100}{90},\\ \\y=\dfrac{70\cdot 90}{100}=\dfrac{6300}{100}=63$

The number of correct answers in Science is 63.

Then the table is

$\begin{array}{cccc} \text{Test} & \text{Number Correct} & \text{Score} & \text{Total}\\ \text{Math} & 68 & 80\% & 85 \\ \text{Science} & 63 & 90\% & 70\end{array}$

2. Marisol had 80% in Math and 90% in Science, then she had the higher score in Science.

3. Suppose Marisol scored a 96% on an english test. There were 50 questions on the test. Consider this task as proportion too

50 -100%

z - 96%

Then

$\dfrac{50}{z} =\dfrac{100}{96},\\ \\z=\dfrac{96\cdot 50}{100}=\dfrac{4800}{100}=48$

She answered correctly 48 questions from English test.