Question

x2 – 8x + 12
Give the final factored form of the expression and provide an explanation.

Answer 1

$x^2-8x+12=\\ x^2-6x-2x+12=\\ x(x-6)-2(x-6)=\\ (x-2)(x-6)$

Answer 2

$x^2-8x+12=0\ \ \ | write\ -8x\ as\ -6x-2x\\\\ x^2-6x-2x+12=0\\\\x(x-2)-6(x-2)=0\\\\(x-6)(x-2)=0\\\\ Factor\ form\ is\ (x-6)(x-2)=0.$