Question

#5.
A rock is thrown straight down with an initial velocity of 14.5 m/s from a cliff. What is the
rock's displacement after 2.0 s? (Acceleration due to gravity is 9.80 m/s'.)

How would I get the answer

Answer 1

Given:

• u = 14.5m/s
• t = 2s
• a= 9.8

We know,

$s = ut \: + \frac{1}{2} a {t}^{2}$

$\implies \: s = 14.5 \times 2 + \frac{1}{2} \times 9.8 \times {2}^{2}$

$\implies \: s = 29 + 9.8 \times 2$

$\implies \: s = 29 + 19.6$

$\implies \: s = 48.6 \: m$