Question

A car with a velocity of 30 mph
right applying its brakes.
An object with a velocity of 10
m/s to the left and forces of 10
N nght and S N left acting on it
An object with a velocity of 10
m/s to the left and forces of 5
N right and 10 N left acting on
it
An object with a velocity of 10
m/s to the right and forces of
10 N right and 5 N left acting
on it
An object with a velocity of 10
m/s to the right and forces of 5
N right and10 N Left acting on
it
An object with a velocity of 5
my's to the left has forces of
100 N left and 50 N right
acting on it.

Answer 1

Answer:

First calculate the deceleration making use of the formulation: V(very last speed= U(initial speed) -a(acceleration) t(ime) so 10=20- 4a. unfavourable a as decelerating. making a the acceleration the challenge by using rearranging the elements 4a= 20-10 = 10 so a=10/4 making use of Newton's 2d regulation P(stress) = M (mass) x A (acceleration). so P = 800 x 10/4 = 8000 /4 = 2000 newtons

Explanation: