Question

An elevator accelerates upward at 1.2 m/s
2
.
The acceleration of gravity is 9.8 m/s
2
.
What is the upward force exerted by the
floor of the elevator on a(n) 92 kg passenger?
Answer in units of N

Answer 1

Answer:

1012 N

Explanation:

There are two forces acting on the passenger.

Normal force N pushing up and weight force mg pulling down.

Apply Newton's Second Law:

∑F = ma

N − mg = ma

N − (92 kg) (9.8 m/s²) = (92 kg) (1.2 m/s²)

N = 1012 N