Consider the equation:
2x^2-20x=x^2-192x
2
−20x=x
2
−192, x, squared, minus, 20, x, equals, x, squared, minus, 19
1) Rewrite the equation by completing the square.
Your equation should look like (x+c)^2=d(x+c)
2
=dleft parenthesis, x, plus, c, right parenthesis, squared, equals, d or (x-c)^2=d(x−c)
2
=dleft parenthesis, x, minus, c, right parenthesis, squared, equals, d.
2) What are the solutions to the equation?
Choose 1 answer:
Choose 1 answer:
(Choice A)
A
x=-10 \pm 81x=−10±81x, equals, minus, 10, plus minus, 81
(Choice B)
B
x=10 \pm 81x=10±81x, equals, 10, plus minus, 81
(Choice C)
C
x=-10 \pm 9x=−10±9x, equals, minus, 10, plus minus, 9
(Choice D)
D
x=10 \pm 9x=10±9
