Explanation:
This problem is solved by determining how long it takes the arrow to fall to the ground in exactly the same manner as if the arrow was dropped with no horizontal velocity. The time required for the arrow to fall to the ground will be the same time that the arrow flies horizontally at 60.0 m/s, so
d=1/2at^2
solved for t=√2d/a
t=√(2)(2.00m)/9.80m/s^2 =0.639s
The time required for the fall is multiplied by the horizontal velocity to get the horizontal distance.
d(horizontal)=v(horizontal)×time=60.0m×0.639s =38.3m