Question

Show that (x-1)(x+2)(x+3) can be written in the form ax^3+bx^2+cx+d where a,b and c are all positive integers, and d is a negative integer

Answer 1

Answer:

The answer is x³ + 4x² + x - 6.

Step-by-step explanation:

You have to expand it :

$(x - 1)(x + 2)(x + 3)$

$= ( {x}^{2} + 2x - x - 2)(x + 3)$

$= ( {x}^{2} + x - 2)(x + 3)$

$= {x}^{3} + 3 {x}^{2} + {x}^{2} + 3x - 2x - 6$

$= {x}^{3} + 4 {x}^{2} + x - 6$

Answer 2

Answer:4x+2x^3-2x

Step-by-step explanation: