Step-by-step explanation:
Hey there!
To solve this type of question, you must take square of variable"X" to right side making it ±squareroot. As it is a quadratic equation it will have two values (±).
Given;
[tex] {x}^{2} = 16[/tex]
Taking (square) to right side. It becomes ± square root.
[tex]x = + - \sqrt{16} [/tex]
[tex]x = + - \sqrt{ {4}^{2} } [/tex]
Cancel square and square root.
[tex]x = + - 4[/tex]
Therefore, X = ±4
Hope it helps...
Answer:
There are two I results found which is x=4 and x=-4
Step-by-step explanation:
Step by Step Solution:
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Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
x^2-(16)=0
Step by step solution :
STEP
1 :
Trying to factor as a Difference of Squares:
1.1 Factoring: x2-16
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 16 is the square of 4
Check : x2 is the square of x1
Factorization is : (x + 4) • (x - 4)
Equation at the end of step
1 :
(x + 4) • (x - 4) = 0
STEP
2 :
Theory - Roots of a product
2.1 A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.
Solving a Single Variable Equation:
2.2 Solve : x+4 = 0
Subtract 4 from both sides of the equation :
x = -4
Solving a Single Variable Equation:
2.3 Solve : x-4 = 0
Add 4 to both sides of the equation :
x = 4 and/or x=-4
