Answer:
The toy car stops after 10 seconds.
Explanation:
Constant Acceleration Motion
It's a type of motion in which the velocity of an object changes uniformly at a rate called acceleration.
Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:
[tex]v_f=v_o+at\qquad\qquad [1][/tex]
The toy car moves at vo=30 cm/s and decelerates at [tex]a=-3\ cm/s^2[/tex]. Note the negative sign of the acceleration that indicates the speed is decreasing over time.
We need to calculate the time needed for the toy car to stop vf=0.
To find the time, we solve [1] for t:
[tex]\displaystyle t=\frac{v_f-v_o}{a}[/tex]
Since all the units of speed and acceleration are in centimeters, we don't need to convert to meters
[tex]\displaystyle t=\frac{0-30}{-3}=10[/tex]
The toy car stops after 10 seconds.