Simple....
you have:
4x+3y≤-12
To solve for X or Y just isolate the variable....
4x+3y≤-12
-3y -3y
4x≤-3y-12
Now divide by 4....
[tex] \frac{4x}{4} \leq \frac{-3y-12}{4} [/tex]
[tex]x \leq -\frac{3y}{4} -3[/tex]
Now for y:
4x+3y≤-12
4x+3y≤-12
-4x -4x
3y≤-4x-12
Divide by 3...
[tex] \frac{3y}{3} \leq \frac{-4x-12}{3} [/tex]
[tex]y \leq -\frac{4x}{3} -4[/tex]
This is the way to solve it.
Thus, your answer.
