Answer:
[tex]part \: a. \\ \boxed{ 4x + 6 } \\ \\ part \: b. \\ \boxed{ 12 \leqslant 4x + 6 \leqslant 36}[/tex]
Step-by-step explanation:
[tex]if \: the \: area \: is \to \\ A = 2(a + b) \\ where \: \to \\ a = 2x \\ b = 3 \\ then \to \\ A = 2(2x + 3) \\ A = 4x + 6 \\ there fore \: the \: equation \: will \: be \: in \: the \: form : \\ \boxed{ 12 \leqslant 4x + 6 \leqslant 36}[/tex]
♨Rage♨
