Answer:
[tex]\displaystyle f(4) + g(3) = 76[/tex]
Step-by-step explanation:
We are given the two functions:
[tex]\displaystyle f(x) = 64\left(\frac{1}{2}\right)^x\text{ and } g(x)=20x+12[/tex]
And we want to find the value of:
[tex]f(4)+g(3)[/tex]
We can find the value of each function individually.
Find f(4):
[tex]\displaystyle \begin{aligned} f(4) & = 64\left(\frac{1}{2}\right)^{(4)} \\ \\ & = 64\left(\frac{1^4}{2^4}\right) \\ \\ & = 64\left(\frac{1}{16}\right) \\ \\ & = 4\end{aligned}[/tex]
Find g(3):
[tex]\displaystyle \begin{aligned} g(3) & = 20(3) + 12 \\ \\ & = (60) + 12 \\ \\ & = 72\end{aligned}[/tex]
Therefore, substitute:
[tex]\displaystyle \begin{aligned} f(4) + g(3) & = (4) + (72) \\ \\ & = 76\end{aligned}[/tex]
Therefore, in conclusion:
[tex]\displaystyle f(4) + g(3) = 76[/tex]