[tex]\bf{ \underline{Given:- }}[/tex]
[tex] \sf{• \: There \: is \: a \: 28 \: resistance \: in \: the \: dryer. \: It \: is \: plugged \: into \: a \: 240 \: V \: circuit. }[/tex]
[tex] \\ [/tex]
[tex]\bf{ \underline{To \: Find :- }}[/tex]
[tex] \sf{• \: How \: much \: current \: passes \: through \: the \: dryer.}[/tex]
[tex] \\ [/tex]
[tex] \huge\bf{ \underline{ Solution :- }}[/tex]
[tex] \sf According \: to \: the \: question, [/tex]
[tex] \sf• \: Resistance \: (R) = 28 \: Ω[/tex]
[tex] \sf• \: Voltage \: (V) = 240 \: v[/tex]
[tex] \bf \red{ \bigstar{ \: Formula \: of \: Current \: (I) = \frac{V}{R}}}[/tex]
[tex] \rightarrow \sf I = \frac{240}{28} [/tex]
[tex] \rightarrow \sf I = 8.57[/tex]
[tex] \\ [/tex]
[tex] \bf \purple{Therefore, \: 8.57 \: Amps. \: current \: passes \: through \: the \: dryer.}[/tex]