Question

There is a spinner with 13 equal areas, numbered 1 through 13. If the spinner is spun
one time, what is the probability that the result is a multiple of 4 or a multiple of 3?

Answer 1

Answer:

6/13

Step-by-step explanation:

There are 13 numbers between 1 and 13.  There are 6 numbers that are multiples of 4 or 3: 3, 4, 6, 8, 9, and 12.

So the probability is 6/13.

Answer 2

Answer:

$the \: probability \: that \: the \: result \: is \: a \\ \: multiple \: of \: 4 \: or \: a \: multiple \: of \: 3 \: is \: \to \\ \boxed{ \frac{7}{13} }$

Step-by-step explanation:

$let \: the \: proberbility \: be : \rho \\ then \: the \: proberbility \: ( \rho) \: is \: given \: as : \\ \rho = \frac{number \: of \: possible \: outcome}{total \: number \: of \: possible \: outcome} \\ where \\ number \: of \: possible \: outcome = 3 + 4 = 7 \\ total \: number \: of \: possible \: outcome = 13 \\ hence : \to \\ \boxed{\rho = \frac{7}{13} }$

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