Question

What is the molarity of a sodium chloride solution that has 2.3 moles of NaCl in a volume of 350 mL?

Answer 1

Answer:

$6.5714\text{M}$

Explanation:

Number of moles of NaCl = 2.3 moles

Volume = 350 mL = $350\times 10^{-3}\ \text{L}=0.35\ \text{L}$

Molarity is given by

$M=\dfrac{\text{Number of moles of NaCl}}{\text{Volume}}$

$\Rightarrow M=\dfrac{2.3}{0.35}$

$\Rightarrow M=6.5714\text{M}$

Molarity of the solution is $6.5714\text{M}$