Question

Two men pull a 31-kg box with forces 9.7 N and 7.6N in the directions shown below. Find the resultant acceleration of the box and the direction in which the box moves.

Answer 1

Answer:

$a=0.067\ m/s^2$

Explanation:

Given that,

Mass of the box, m = 31 kg

The two forces are shown in the attached figure. They are acting in opposite direction.

Net force, F = 9.7 - 7.6 = 2.1 N

The formula for net force is given by :

F = ma

a is resultant acceleration

$a=\dfrac{F}{m}\\\\a=\dfrac{2.1}{31}\\\\a=0.067\ m/s^2$

So, the resultant acceleration is $0.067\ m/s^2$.