Answer:
(2, -11)
Step-by-step explanation:
[tex]f(x)=3x^2-12x+1\\\\f(x)=3(x^2-4x)+1\\\\f(x)=3(x^2-2\cdot x\cdot2+2^2-2^2)+1\\\\f(x)=3(\underline{x^2-4x+4}-4)+1\\\\f(x)=3[(x-2)^2-4]+1\\\\f(x)=3(x-2)^2-12+1\\\\f(x)=3(x-2)^2-11[/tex]
the vertex form of parabola's equation is: f(x) = a(x - h)² + k with vertex (h,k)
x-h = x-2 ⇒ h = 2
+k = -11 ⇒ k = 11
