Question

6. A gas occupies a volume of 125.0 mL at 10.0C. At what temperature would the volume be 50.0 mL?

Answer 1

Answer:

V1= 125.0mL    125.0mL/10.0C=50.0mL/T2

T1= 10.0C         T2=(125.0mL/10.0C) X 50.0mL

V2= 50.0mL       T2= 625L

T2=?

Explanation:

I'm pretty sure about this It took me a while to get it but I already took the test