Question

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find out the time at which the rocket will reach its max, to the nearest 100th of a second.
Equation:
y=-16x^2+267x+107

Answer 1

Answer:

The rocket will reach the maximum height after 8.34 seconds.

Step-by-step explanation:

We need to take the derivative of the function and set it to 0.

$y' = -32x + 267 = 0\\32x = 267\\x = 8.34$