Complete question :
A local bakery has determined a probability distribution for the number of cheesecakes it sells in a given day. The distribution is as follows:
Number sold in a day 0 5 10 15 20 Prob (Number sold) 0.06 0.2 0.13 0.08 0.53
Find the number of cheesecakes that this local bakery expects to sell in a day.
A) 20 B) 14.1 C) 14.16 D) 10
Answer:
Given the data:
14.1
Step-by-step explanation:
X : ____0 ___5 ____10 _____15 _____20
P(X): _0.06 _0.2 __0.13 ___ 0.08 ____ 0.53
Exoectwd number of cheesecakes to be sold per day :
E(X) = ΣX*P(x)
E(X) = (0*0.06) + (5*0.2) + (10*0.13) + (15*0.08) + (20*0.53)
E(X) = 0 + 1 + 1.3 + 1.2 + 10.6
E(X) = 14.1
The number of cheesecakes that this local bakery expects to sell in a day is 14.1.
Question is looks like incomplete the complete question is,
Complete question :
A local bakery has determined a probability distribution for the number of cheesecakes it sells in a given day. The distribution is as follows:
Number sold in a day 0 5 10 15 20 Prob (Number sold) 0.06 0.2 0.13 0.08 0.53
Find the number of cheesecakes that this local bakery expects to sell in a day.
A) 20 B) 14.1 C) 14.16 D) 10
We have given data is,
X : 0 5 10 15 20
P(X): 0.06 0.2 0.13 0.08 0.53
E(X) = ΣX*P(x)
Therefore by using the formula we get,
E(X) = (0*0.06) + (5*0.2) + (10*0.13) + (15*0.08) + (20*0.53)
E(X) = 0 + 1 + 1.3 + 1.2 + 10.6
E(X) = 14.1
Therefore,the number of cheesecakes that this local bakery expects to sell in a day is 14.1
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