Question

Mr.Cunningham built himself an ice rink that is 14 and 2/5 meters long and 6 and 7/8 meters wide. What is the area of the ice rink Mr.Cunningham built?

Answer 1

Answer: 99 sq., meters.

Step-by-step explanation:

Given: For ice rink, Length = $14\dfrac25\text{meters}=\dfrac{14\times5+2}{5}=\dfrac{72}{5}\text{meters}$

Width = $6\dfrac78\text{meters}=\dfrac{8\times6+7}{8}=\dfrac{55}{8}\text{meters}$

Now, Area of ice rink = length x width

$=\dfrac{72}{5}\times\dfrac{55}{8}=\dfrac{9}{1}\times\dfrac{11}{1}=99\text{ sq. meters}$

Hence, the area of the ice rink Mr.Cunningham built = 99 sq., meters.