Answer: [tex]a_{n}=653+(n-1)608[/tex]
Step-by-step explanation: This sequence of numbers is an arithmetic progression: a sequence of numbers in which the last number is the previous number plus a constant factor.
For example, the sequence:
653 1261 1869 2477 3085 3693
if you subtract each term with its previous number, the result will be 608:
1261 - 653 = 608
1869 - 1261 = 608
...
33693 - 3085 = 608
For a general arithmetic progression, the nth value is
[tex]a_{n}=a_{0}+(n-1)r[/tex]
where
[tex]a_{n}[/tex] is the wanted value
[tex]a_{0}[/tex] is the first value
n is number of terms or values
r is constant factor
For the sequence above, nth value is:
[tex]a_{n}=653+(n-1)608[/tex]
The algebraic expression for the nth value in this sequence is [tex]a_{n}=653+(n-1)608[/tex].