Question

Find the standard​ deviation, ​, for the binomial distribution which has the stated values of n and p. Round your answer to the nearest hundredth. n​503; p0.7

Answer 1

Answer: 10.28

Step-by-step explanation:

For the binomial distribution ,

standard deviation : $\sigma=\sqrt{p(1-p)n}$, where p = population proportion, n = sample size.

Given:  n= 503 and p=0.7

Then, $\sigma=\sqrt{503\times0.7(1-0.7)}=\sqrt{105.63}\approx10.28$

Hence, the  standard​ deviation = 10.28