How do i find angle equation of angle bisector with 2 angles? I have 2 angle, 50° and 3x+1. How do i make an solvable equation with it? Sorry for my bad english!

Respuesta :

Answer:

50° = 3x + 1, and x ≅ [tex]16.3^{o}[/tex]

Step-by-step explanation:

An angle bisector divides a given angle into two equal part in degrees.

Now, given that we have <ABC which has been bisected into two angles 50° and 3x + 1.

Since the two angles are equal, then;

50° = 3x + 1   (bisection property of an angle)

So that,

50° - 1 = 3x

49 = 3x

Divide both sides by 3, to have;

x = [tex]\frac{49}{3}[/tex]

  = [tex]16.3^{o}[/tex]

Therefore, the value of x is approximately [tex]16.3^{o}[/tex].

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