Answer:
velocity relative to the ground = 2.54 m/s
Explanation:
given data
still water Vx = 2.30 m/s
across a steam Vy = 1.20 m/s
solution
we get here first velocity relative to the ground is express as
velocity = [tex]\sqrt{Vx^2+Vy^2}[/tex] ...............1
put here value and we get
velocity = [tex]\sqrt{2.3^2+1.20^2}[/tex]
velocity = 2.54 m/s