Answer:
3886.53 [tex]m^{2}[/tex]
Step-by-step explanation:
The running track consist of two semicircles and a rectangle.
So that;
Diameter of the semicircles = width of the rectangle = 73 m
radius = [tex]\frac{diameter}{2}[/tex]
= [tex]\frac{73}{2}[/tex]
= 36.5 m
But the two semicircles form a circle, so that;
Circumference of a circle = 2[tex]\pi[/tex]r
Circumference of the circle formed by the semicircles = 2 x [tex]\frac{22}{7}[/tex] x 36.5
= 229.43 m
Thus,
length of the running track = circumference of the circle formed + length of the two sides of the rectangle
= 229.43 + 84.39 + 84.39
= 398.21 m
The length of the running track is 398.21 m.
Therefore;
Area of the running track = length x width
= 398.21 x 9.76
= 3886.5296
The area of the running track is 3886.53 [tex]m^{2}[/tex].